How do you simplify #\frac{32\div 4- ( - 28) \div 7}{12\div ( - 4)}#?

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Answer 1 · 2017-06-11T14:21:27

#-4#

#(32-:4-(-28)-:7)/((12-:(-4))#

#:.=(8-(-28)-:7)/-3#

#:.=(8+28-:7)/-3#

#:.=(8+4)/-3#

#:.=12/-3#

#=-4#

Answer 2 · 2017-06-12T06:10:07

Use bedmas: the answer is #-4#

First, group the terms.

you get: #32/4-(-28/7)#for the numerator,

which is equal to #8-(-4)=12#.

Now the denominator.

Now, #12/-4=-3.#

So, it's #12/-3# which is equal to #-4#

Answer 3 · 2017-06-12T09:49:03

#-4#

Identify the separate terms first.

Although this is all one term because it is a fraction, there are separate terms in the numerator.
Simplify each term separately.

#(color(red)(32 div4) - color(blue)((-28)div7))/(color(green)(12div (-4))#

#=(color(red)(8) -color(blue)((-4)))/(color(green)(-3))#

#=(color(red)(8) color(blue)(+4))/(color(green)(-3))#

#= -12/3#

#=-4#