Prove or disprove ? f(AB)=f(A)f(B)
1 Answer
Jun 12, 2017
This identity is generally false...
Explanation:
In general this will be false.
A simple example would be:
f(x)=2
Then:
f(11)=2≠1=22=f(1)f(1)
Bonus
For what kind of functions
Note that:
f(1)=f(11)=f(1)f(1)=1
f(0)=f(0x)=f(0)f(x) for anyx
So either
If
f(x)=xn
Then:
f(ab)=(ab)n=anbn=f(a)f(b)
There are other possibilities for
f(x)=|x|c for any real constantc
f(x)=sgn(x)⋅|x|c for any real constantc