Question

Describe how the graph of `h(t)=-0.8t^2+20` can be transformed onto the graph of `h(t)=-5t^2+20` ? (urgent?)

Thank you :).

Answer 1

This is not a vertical expansion because the 20 was not touched. We can however, horizontally compress this function.

`5/0.8 = 6.25` this is to find the stretch value after getting squared (`y=-0.8(6.25t^2)+20`)

`sqrt(6.25) = 2.5` this is to find the stretch value before getting squared ( `y=-0.8(2.5t)^2 +20`)

So there was a horizontal compression by a factor of 2.5