Question

How do you solve `x^ { 2} + 4x - 13= 5`?

Answer 1

As follows

Explanation:

`x^2+4x-13=5`
`x^2+4x-18=0`
`x^2+2(2)x+(2)^2-(2)^2-18=0`
`(x+2)^2-4-18=0`
`(x+2)^2=22`
`x+2=+-sqrt22`
`x=-2+-sqrt22`