Question

How do you write the standard from of the equation of the circle given Center is (-2,-3) and radius is: 3?

Answer 1

The standard Cartesian form for the equation of a circle is:

`(x - h)^2+ (y-k)^2 = r^2" [1]"`

Where `(h,k)`is the center and r is the radius

Explanation:

Substitute - 2 for h, -3 for k, and 3 for r in equation [1]:

`(x - (-2))^2+ (y-(-3))^2 = 3^2" [2]"`

Here is a graph of the equation:

graph{(x - (-2))^2+ (y-(-3))^2 = 3^2 [-15, 5, -9, 1]}