Question

How do you write `y = -3/2x + 3` in standard form?

Answer 1

`3x+2y=6`

Explanation:

Standard Form looks like :
`ax+by=c`
where `a,b` and `c` are constants.

So we need to rearrange the formula to get both `x` and `y` to one side, and a number on the other side.

So from:

`y=-3/2x+3`

We should get rid of the fraction first. To do this, multiply everything by 2:

`2y=2(-3/2x)+2(3)`

`=>2y=(2*-3)/2x+6`

`=>2y=(cancel(2)*-3)/cancel(2)x+6`

`=>2y=-3x+6`

Then we bring -3x to the other side by adding 3x to both sides:

`=>3x+2y=-3x+6+3x`

`=>3x+2y=cancel(-3x)+6+cancel(3x)`

`=>3x+2y=6`

And you've got it in standard from now