Question

How do you simplify `\frac { 16y ^ { 4} z ^ { 4} } { 8y z ^ { 6} }`?

Answer 1

`(2y^3)/z^2`

Explanation:

Factorise by the common factor `8yz^4`

`(8yz^4(2y^3))/(8yz^4(z^2))`

Cancel out the common factor

`(cancel(8yz^4)(2y^3))/(cancel(8yz^4)(z^2))`

`(2y^3)/z^2`