How do you find the limit of #2x+5# as #x->-7#?

1 Answer
Jun 15, 2017

Please see below.

Explanation:

When #x# is very close to #-7#,

#2x# is very close to #2(-7) = -14#,

so #2x+5# is very close to #-14+5 = -9#.

The limit is #-9#.

In the end, we get the same number as we get by substitution #-7# for #x#.

For some functions, we do not get the same result by substitution. So it is helpful to understand the slightly different reasoning for limit and substitution.