A particle start from rest moved with constant acceleration for 15second. if it cover s1 distance in first 5second then distance s2 in next 10second ,then find the relation between s1 and s2?

1 Answer
Jun 15, 2017

s_1=0.5625s_2

Explanation:

We use the kinematic expression
s=ut+1/2at^2
The particle starts from rest. Therefore, this expression reduces to
s=1/2at^2

From the given data, distance moved in first 15s
s(15)=s_1=1/2xxaxx15^2
=>s_1=112.5a ........(1)

and distance moved in 25s
s(25)=1/2xxaxx25^2
Therefore, distance moved in next 10s

s_2=1/2xxaxx25^2-1/2xxaxx15^2
=>s_2=1/2xxaxx(25-15)(25+15)
=>s_2=200a ......(2)
Dividing (1) with (2) we get
s_1/s_2=(112.5a)/(200a)
=>s_1=0.5625s_2