Question

Question #583f8

Answer 1

I think you need to pay `$28.40`

Explanation:

You need to pay:
`$20.00` for the first `250g`
then you need to pay:
`3xx$2.80=$8.40`
to add
`3xx250g=750g`

(if you try only `2xx250g=500g` you are short of `50g` in the total and I do not think they are going to let it pass!)

giving a total of:

`$20.00+$8.40=$28.40`

to reach a total weight of:

`750+250=1000g`

that is `200g` more than you have to send but....

Answer 2

`$26.16`

Explanation:

Let's break down the information given:

We are given:

The cost for the first `250"g"` given to be `$20.00`

The cost for every additional `250"g"` to be `$2.80`

We want to find:

I'm the cost for the postage when it weighs `800"g"`

We can write the following equation:

`"C"=2.80a+20`

In this equation, `a` represents the cost for the additional `250"g"` added to the postage. We initially start with `250"g"` with no or `0` additional weight `250"g"` so to determine the cost of the postage we substitute in `0` for `a`:

`"C" = 2.80(0)+20`

`"C"=20` (In dollars)

This makes sense because we were given that the first `250"g"` with nothing extra is set at `$20.00`

Yet there is still something missing. We don't exactly know what `a` Is. We defined `a` to be the additional cost per `250"g"` added to our initial package of the same weight.

We can however, come up with this equation:

`550=250a`

Here `550` is the weight of the package remaining that we have yet to pay for because `800-250=550` since the first `250"g"` is already covered .
`250` represents the additional weight multiplied by `a` which tells us how many more per `250"g"` we need to pay for.

We then solve for `a`

`550/250=cancel(250/250)a`

`2.2=a`

Thus, we have an additional postage rate of `2.2` per `250"g"` to pay for.

Lastly we need to find the cost. Recall the first equation and now we can plug in `a` to find the final cost `"C"`

`"C"=2.80(2.2)+20`

`"C" = 26.16` (In dollars)

So if the package weighs `800"g"` the postage will cost you `$26.16` to send.