Question

How do you simplify `Log(100.0/5.7)`?

Answer 1

`log(100/5.7)=color(magenta)(2-log(5.7))`

Explanation:

(I am assuming the standard usage: `log` means `log_10`)

`log(a/b)=log(a)-log(b)`

`log_10(100)=color(blue)2color(white)("XXXX")`since `10^color(blue)2=100`

Therefore
`color(white)("XXX")log_10(100/5.7)=2 - log_10(5.7)`

Note that there is no simple evaluation for `log_10(5.7)`
but if necessary you could use a calculator to determine
`color(white)("XXX")log(5.7)~~0.755874856`
and from there
`color(white)("XXX")log_10(100/5.7)=2-log_10(5.7)~~1.244125144`