Question

Determine the molarity of a solution formed by dissolving 648 mg of MgCl2 in enough water to yield 150.0 mL of solution?

Answer 1

Approx. `0.05*mol*L^-1` with respect to `"magnesium chloride."`

Explanation:

`"Molarity"="Moles of solute"/"Vollume of solution"`

`=((648xx10^-3*g)/(95.21*g*mol^-1))/(150.0xx10^-3*L)=??*mol*L^-1`.

What is the concentration with respect to `Cl^-`?