How do you solve \frac { 1} { 3} ( 3y + 3) - \frac { 3} { 8} = \frac { 3} { 4} y?

1 Answer

y=-5/2

Explanation:

1/3(3y+3)-3/8=3/4y
Distribute 1/3 to (3y+3).
y+1-3/8=3/4y
[Left Side] Combine the constants 1 and -3/8. Multiply 1 by 8/8 to give both constants the same denominator.
y+(1*8/8)-3/8=3/4y
y+8/8-3/8=3/4y
You can now evaluate 8/8-3/8.
y+5/8=3/4y
Multiply the equation by 8 to cancel out the fractions.
8(y+5/8=3/4y)
8y+5=6y
Move all variables to one side and all constants to the other side and solve.
2y=-5
y=-5/2