A stone is dropped freely, while another thrown vertically downward with an initial velocity of 2m/s from the same point, simultaneously. What is the time required by them to have a distance of 22 m between them?
1 Answer
Explanation:
We're asked to find the time
The equation for the position of stone 1 (the one dropped from rest) is
(the initial
and that of stone 2 (the one launched downward) is
Plugging in the known values, these equations become
At any given time, the position of stone 2 will always be farther than that of stone 1, because it was launched with an initial velocity downward. Since we want to find when the distance between them is
Substituting the above equations for
Thus, the distance between the objects will be
We can check to see if this answer is correct by finding their positions at time