How many mL of a .10 M #NaOH# solution are needed to neutralize 15 mL of .20 M #H_3PO_4# solution?

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Answer 1 · 2017-06-19T21:48:58

30 mL

Use the formula #M_AV_A = M_BV_B#.

#M_A =# Molarity of acid, #V_A =#Volume of acid
#M_B =# Molarity of base, #V_B =#Volume of base

1. Plug known values into the formula.

#(.20)(15) = .10(x)#

2. Solve for x.

#3 = .10x#
#x = 30#

30 mL is your answer.