How do you solve the system of equations #3x + 2y = - 3# and #12x + 8y = - 4#?

1 Answer
Jun 20, 2017

No solution

Explanation:

Divide the second equation by 4. It becomes 3x +2y= -1.

Now compare the slopes of both the straight lines represented by these equations. To do this, solve for y,

the first equation becomes, #y= -3/2 x -3/2#
the second equation becomes #y= -3/2 x -1/2#

The slopes of both lines are same #-3/2#. This means both are parallel and will never meet. Hence no solution.