How do you add #4+ 2\sqrt { 12}#?

1 Answer
Jun 21, 2017

#4+4sqrt(3) ~~ 10.93#

Explanation:

The square root of a product is the product of the multipliers' square roots.

#sqrt(12)=sqrt(4*3)=sqrt(4)*sqrt(3)=2sqrt(3)#

Substitute back into original expression and simplify the second term.

#4 + 2(2sqrt(3)) = 4 + 4sqrt(3)#

There's nothing left to be simplified, and #sqrt(3)# is irrational, so the answer is approximately.

#4+4sqrt(3) ~~ 10.93#