Question

A enjoyed two types of games, `type A` and `type B`, at the game studio. Each time he played `type A`, it cost `Rs. 3` and each time she played `type B`, it cost `Rs. 4`. If the number of `type B` games played was the half of the number of `type A`..?

A enjoyed two types of games, `type A` and `type B`, at the game studio. Each time he played `type A`, it cost `Rs. 3` and each time she played `type B`, it cost `Rs. 4`. If the number of `type B` games played was the half of the number of `type A` games played by him, and the total amount spent was `Rs. 20`, write a system of linear equations for the problem of finding the number of times she played each type of game.

Answer 1

Type A= 4 times and Type B=2 times

Explanation:

Let Type A game played `x` times and Type B game played `y` times.

Then,
`3x+4y=20`------(i)

Also,
Number of Type B games played was half the number of Type A game played, So,
`y=1/2 x`

Substituting `y` into (i):
`3x+4xx1/2 x = 20`
`3x+2x=20`
`5x=20`
`x=4`

Therefore:
`3xx4+4y=20`
`4y=20-12`
`y=8/4`
`y=2`

Hence, Type A 4 times and Type B 2 times.