How do you solve #x/-5 - 45=6#?

1 Answer
Jun 22, 2017

See a solution process below:

Explanation:

Step 1) Add #color(red)(45)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#x/-5 - 45 + color(red)(45) = 6 + color(red)(45)#

#x/-5 - 0 = 51#

#x/-5 = 51#

Step 2) Multiply each side of the equation by #color(red)(-5)# to solve for #x# while keeping the equation balanced:

#color(red)(-5) xx x/-5 = color(red)(-5) xx 51#

#cancel(color(red)(-5)) xx x/color(red)(cancel(color(black)(-5))) = -255#

#x = -255#