Question #9b514

1 Answer
Jun 23, 2017

See below.

Explanation:

Hardy Weinberg principle states that allele frequencies in a population are stable and is consistent from generation to generation.

Sum total of all the allelic frequencies is 1. In a diploid cell, p and q represent the frequency of allele A and a.

The frequency of AA individuals is simply p^2.

Similarly of aa is q^2, of Aa is 2pq.

Hence p^2 + q^2 + 2pq = 1.


1] Allele frequency of R is 20%.
Which means p = (20/100) = 0.2

Now, p + q = 1
q = 0.8

The frequency of RR, i.e p^2 = (0.2)^2 = 0.04.

The frequency of rr, i.e q^2 = (0.8)^2 = 0.64.

The frequency of Rr, i.e 2pq = (2)(0.2)(0.8) = 0.32

2] Total number of individuals = 400
Number of homozygous recessive individuals = 9

Frequency of homozygous individuals i.e, q^2 = (9/400) = 0.0225.

Frequency of the allele q = sqrt(0.0225) = 0.15

Frequency of p = 1 - q = 0.85


I answered two of them. Try the others as I've told you the concept. If you get stuck on any of them let me know.