Points A and B are at (8 ,3 ) and (5 ,7 ), respectively. Point A is rotated counterclockwise about the origin by pi/2 and dilated about point C by a factor of 3 . If point A is now at point B, what are the coordinates of point C?

1 Answer
Jun 23, 2017

The point C=(-7,17/2)

Explanation:

The matrix of a rotation counterclockwise by 1/2pi about the origin is

((0,-1),(1,0))

Therefore, the transformation of point A is

A'=((0,-1),(1,0))((8),(3))=((-3),(8))

Let point C be (x,y), then

vec(CB)=3 vec(CA')

((5-x),(7-y))=3((-3-x),(8-y))

So,

5-x=3(-3-x)

5-x=-9-3x

2x=-14

x=-7

and

7-y=3(8-y)

7-y=24-3y

2y=24-7

y=17/2

Therefore,

point C=(-7,17/2)