How do you evaluate the expression if x=3, y=6, and z=8 given # -xy/z#?
1 Answer
Jun 23, 2017
Explanation:
#-x y/z=-(xy)/z#
#rArr-(3xx6)/8=-18/8=-9/4#
#-x y/z=-(xy)/z#
#rArr-(3xx6)/8=-18/8=-9/4#