Question

What is the percent by mass of `NaHCO_3` in a solution containing 50 g `NaHCO_3` dissolved in 750 mL of water?

Answer 1

6.25%

Explanation:

A solution is a homogeneous mixture consisting of a solute and solvent. The solution is typically defined by the amount of solute dissolved into an amount of 'solution'. So calculating the percent component in the solution would be ...

Wt% of component = `(("Weight" "of" "Component")/("Weight""of""Solution"))xx100%`

where (Solute Wt + Solvent Wt) = Solution Wt.

For this problem ...

`Wt% "NaHCO_3 = ((50 g NaHCO_3)/((50g + 750g)Solution))xx100% =`6.25% by weight