If a rocket with a mass of 4000 tons vertically accelerates at a rate of # 4/7 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 8 seconds?

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Answer 1 · 2017-06-24T06:35:32

The power is #=10.5MW#

We apply Newton's Second Law to find the force

#F=ma#

The mass is #m=4000*1000kg=4*10^6kg#

The acceleration is #a=4/7ms^-2#

The force is

#F=ma=4*10^6*4/7=2.29*10^6N#

We apply the equation of motion

#v=u+at#

to calculate the speed at #t=8s#

#v=0+4/7*8=4.57ms^-1#

The power is

#P=Fv#

#P=2.2910^6*4.57=10.5*10^6W#

#=10.5MW#