Question #14cfe

1 Answer
Jun 24, 2017

AS #a/v^2# is added with P, the pressure .This term #a/v^2# will have unit of pressure.
Again #v# is the molar volume . so unit of #v# may be #Lmol^-1#

If the unit of pressure #P# is taken as #atm#, then unit of a will be

#"Unit of a"="Unit of "Pxx "Unit of " v^2=atmL^2mol^-2#

If the unit of pressure #P# is taken as #Pa=Nm^-2# and unit of molar volume as #m^3mol^-1#, then unit of a will be

#"Unit of a"="Unit of "Pxx "Unit of " v^2#

#=Nxxm^-2m^6mol^-2#

#=Nxxm^4mol^-2#