Question

How do you solve `5x + 35= 10x`?

Answer 1

See a solution process below:

Explanation:

First, subtract `color(red)(5x)` from each side of the equation to isolate the `x` term while keeping the equation balanced:

`-color(red)(5x) + 5x + 35 = -color(red)(5x) + 10x`

`0 + 35 = (-color(red)(5) + 10)x`

`35 = 5x`

Now, divide each side of the equation by `color(red)(5)` to solve for `x` while keeping the equation balanced:

`35/color(red)(5) = (5x)/color(red)(5)`

`7 = (color(red)(cancel(color(black)(5)))x)/cancel(color(red)(5))`

`7 = x`

`x = 7`