Question #010fe

1 Answer
Jun 26, 2017

Transform the equation to factored form, and answer the following questions.

Explanation:

Basically, what they're asking is to transform the equation to vertex form, and answer the following questions using the now-transformed equation.

#f(x)=1/2x^2+1/2x-10#


Intercept Form

Intercept form is another way to say factored form. This involves factoring.

First, let's factor out the GCF - #1/2#.

#f(x)=1/2x^2+1/2x-10#

#f(x)=1/2(x^2+x-20)#

Now it's a simple trinomial. "What two numbers added equal #b#, and multiplied equal #c#?"

In this case, it is #5# and #-4#.

#f(x)=1/2(x+5)(x-4)#

This is the factored form (AKA intercept form).

If we expand the brackets, we will get the standard form.


Zeros

In order to find the #x#-intercepts, the most simplest method is to use the quadratic formula.

#x = (-b+-sqrt(b^2-4ac))/(2a)#

Here, we sub in the values from a standard equation.

#x = (-(1/2)+-sqrt((1/2)^2-4(1/2)(-10)))/(2(1/2))#

We simplify.

#x = (-1/2+-sqrt(81/4))/(1)#

And solve for #x#.

#x [+] = 4#

#x [-] = -5#

If we graph it, we can conclude that the zeros are #4# and #-5#.


Vertex

To find the vertex, in my opinion, the easiest way is to complete the square.

First, we factor out the #a#-value from the first two terms.

#f(x)=1/2x^2+1/2x-10#

#f(x)=1/2(x^2+x)-10#

Now, we divide the #b#-value by two, and the square it. In the end, we still get one. We must add and subtract those values in order to keep the equation true to itself.

#f(x)=1/2(x^2+x + 1/4 - 1/4)-10#

Now we expand the #-1/4#.

#f(x)=1/2(x^2+x + 1/4) -1/8 -10#

Now we simplify the equation.

#f(x)=1/2(x + 1/2)^2 -81/8#

That's our vertex form. If we expand it, we would get the standard form.

Since we have our vertex formula, we can just use the #h# and the #k#-values where #(h,k)# = #(x, y)#.

Thus, the vertex is #(-1/2, -81/2)#.

If we graph it, we can conclude the that vertex is indeed #(-1/2, -81/2)#.


Axis of Symmetry

The axis of symmetry is basically the #x#-value of the vertex.

Thus, it is: #x=-1/2#.


Here's a graph.

graph{1/2x^2+1/2x-10 [-10, 10, -5, 5]}


Hope this helps :)