Question

A rectangle has a width that is twice as long as its length and of 722 square inches. What the length of a diagonal?

Answer 1

42.49in

Explanation:

Total area is `x*2x=2x^2=722`, `x^2=361`, `x=sqrt(361)=19`.

Two sides = 19 and 38.

Pytahgorus is now needed for the diagonal, because `a^2+b^2=c^2`, where `c=sqrt(a^2+b^2)=sqrt(19^2+38^2)=sqrt(361+1,444)=sqrt(1,805)=42.4852916~~42.49`.

Therefore, the diagonal is roughly 42.49in.