Question

Question #9da19

Answer 1

`x=`any number

Explanation:

First, re-write `x` as `e^lnx`
This gives us: `(e^lnx)^(1/lnx)`

Then, we simplify using index laws:
`e^{1/lnx*lnx}=> e^{lnx/lnx}`
now we have simplified this to `e^{lnx/lnx}` therefore, this works for any x value that you plug in because they always cancel out to give 1 in the index.