How do you solve #4( t - 1) + 2( t - 4) = 18#?

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Answer 1 · 2017-06-29T08:11:38

#t = 5#

#4(t-1) + 2(t-4) = 18#

#4t - 4 + 2t- 8 = 18#

#4t - 4 + 2t = 18 + 8#

#4t + 2t = 26 + 4#

#6t = 30#

#(color(red)(cancel(color(black)(6)))t) /color(red)(cancel(6)) = 30/6#

#color(blue)(t = 5#

Now we can input the number to prove that #t = 5#.

#4(5 -1) + 2(5 -4) = 18#

#4 xx 4 + 2 xx 1 = 18#

#16 + 2 = 18#