Question

Question #b3e6c

Answer 1

Right now you have `tantheta*costheta*csctheta=1`

Considering `tantheta = sintheta/costheta` we can rewrite the equation to `(sintheta)/(costheta)*costheta*csctheta`

Also, `csctheta = 1/sintheta`, so it can be rewritten again as `(sintheta)/(costheta)*costheta/sintheta`. As the top and bottom both perfectly cancel, you get 1.

Answer 2

`"see explanation"`

Explanation:

`"using the following "color(blue)"trigonometric identities"`

`• tanx=(sinx)/(cosx)`

`• cscx=1/(sinx)`

`"left side " =tanxcosxcscx`

`color(white)("left sidexx")=(cancel(sinx)^1)/cancel(cosx)^1xxcancel(cosx)^1/1xx1/cancel(sinx)^1`

`color(white)(xxxxxxx)=1=" right side"`