How do you write the quadratic function in standard form #y=(x+1)(x+2)#?

1 Answer
Jun 30, 2017

See a solution process below:

Explanation:

To write this in standard form you multiply the two terms on the right side of the equation by multiplying each individual term in the left parenthesis by each individual term in the right parenthesis.

#y = (color(red)(x) + color(red)(1))(color(blue)(x) + color(blue)(2))# becomes:

#y = (color(red)(x) xx color(blue)(x)) + (color(red)(x) xx color(blue)(2)) + (color(red)(1) xx color(blue)(x)) + (color(red)(1) xx color(blue)(2))#

#y = x^2 + 2x + 1x + 2#

We can now combine like terms:

#y = x^2 + (2 + 1)x + 2#

#y = x^2 + 3x + 2#