How do you divide #\frac { 4b } { 9c } \div \frac { 2b c } { 3c ^ { 5} }#?

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Answer 1 · 2017-07-01T05:37:29

#(2c^3)/3#

To divide fractions, you can multiply the reciprocal (flip) of the second fraction. This makes the expression

#(4b)/(9c)*(3c^5)/(2bc#

Now multiply the numerators and denominators together

#(12c^5b)/(18c^2b)#

This can now be simplified by getting rid of the common variables:

#(2*cancel6cancelc^2*c^3cancelb)/(3*cancel6cancelc^2cancelb)#

You are then left with #(2c^3)/3#