How do you solve #3y - \frac { 2y } { 3} = 28#?

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Answer 1 · 2017-07-01T06:05:51

#y=12#

#3y-(2y)/3=28#

Multiply all terms by #3#.

#3xx3y-3xx(2y)/3=3xx28#

#9y-1cancel3xx(2y)/(1cancel3)=84#

#9y-2y=84#

#7y=84#

Divide both sides by #7#.

#(7y)/7=84/7#

#(1cancel7y)/(1cancel7)=12#

#y=12#