Question

If `6*g` urea is dissolved in `1*L` of water, what is the resultant concentration?

Answer 1

Well `"concentration"` `=` `"Moles of solute"/"Volume of solution"`

Explanation:

And urea `O=C(NH_2)_2` has a molar mass of `60.06*g*mol^-1`.

And thus `[O=C(NH_2)_2]=((6*g)/(60.06*g*mol^-1))/(1*L)=0.010*mol*L^-1`.

I presume the solvent is water......in which it has some considerable solubility.