Question #dbca2

1 Answer
Jul 1, 2017

#frac(a + a b + c)(b + 1)#; #a, b, c > 0#

Explanation:

We have: #a + frac(1)(frac(b + 1)(c))#

#= a + 1 cdot frac(c)(b + 1)#

#= a + frac(c)(b + 1)#

#= frac(a (b + 1))(b + 1) + frac(c)(b + 1)#

#= frac(a + a b + c)(b + 1)#; #a, b, c > 0#