If #(3x-2)^2 + 1 = 50#, then what is #20-2x#?

1 Answer
Jul 1, 2017

There are two possible solutions:

#50/3#, or #14#

Explanation:

We have:

# (3x-2)^2 + 1 = 50 #
# :. (3x-2)^2 = 49 #
# :. 3x-2 = +-7 #
# :. 3x = 2+-7 #
# :. x = 2/3+-7/3 #
# :. x = -5/3, 3 #

And so #y=20-2x# is:

# y=20-10/3, 20-6 #
# \ \=50/3, 14 #