How do you evaluate the function when x = -3, 0, and 2 for g(x) = -9x + 1?

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Answer 1 · 2017-07-02T00:05:39

See a solution process below:

To evaluate the function you need to replace the value of #x# for #x# in the function #g(x)#.

1) #x = -3#; substitute #color(red)(-3)# for #color(red)(x)# in #g(x)#:

#g(color(red)(x)) = -9color(red)(x) + 1# becomes:

#g(color(red)(-3)) = (-9 * color(red)(-3)) + 1#

#g(color(red)(-3)) = 27 + 1#

#g(color(red)(-3)) = 28#

2) #x = 0#; substitute #color(red)(0)# for #color(red)(x)# in #g(x)#:

#g(color(red)(x)) = -9color(red)(x) + 1# becomes:

#g(color(red)(0)) = (-9 * color(red)(0)) + 1#

#g(color(red)(0)) = 0 + 1#

#g(color(red)(0)) = 1#

2) #x = 2#; substitute #color(red)(2)# for #color(red)(x)# in #g(x)#:

Try this one and see if the previous two examples showed you how to evaluate the function. Good luck!