How do you solve for x: #6y = 5x - 3z#?

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Answer 1 · 2017-07-02T19:21:40

See a solution process below:

First, add #color(red)(3z)# to each side of the equation to isolate the #z# term while keeping the equation balanced:

#6y + color(red)(3z) = 5x - 3z + color(red)(3z)#

#6y + 3z = 5x - 0#

#6y + 3z = 5x#

Now, divide each side of the equation by #color(red)(5)# to solve for #x# while keeping the equation balanced:

#(6y + 3z)/color(red)(5) = (5x)/color(red)(5)#

#(6y + 3z)/5 = (color(red)(cancel(color(black)(5)))x)/cancel(color(red)(5))#

#(6y + 3z)/5 = x#

#x = (6y + 3z)/5#