How do you solve #3x + 4< 2x + 8#?

1 Answer
smendyka
Jul 2, 2017

See a solution process below:

Explanation:

Subtract #color(red)(4)# and #color(blue)(2x)# from each side of the inequality to solve for #x# while keeping the inequality balanced:

#-color(blue)(2x) + 3x + 4 - color(red)(4) < -color(blue)(2x) + 2x + 8 - color(red)(4)#

#(-color(blue)(2) + 3)x + 0 < 0 + 4#

#1x < 4#

#x < 4#

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