How do you solve #3d + 1= 13#?

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Answer 1 · 2017-07-02T19:36:14

See a solution process below:

Step 1) Subtract #color(red)(1)# from each side of the equation to isolate the #d# term while keeping the equation balanced:

#3d + 1 - color(red)(1) = 13 - color(red)(1)#

#3d + 0 = 12#

#3d = 12#

Step 2) Divide each side of the equation by #color(red)(3)# to solve for #d# while keeping the equation balanced:

#(3d)/color(red)(3) = 12/color(red)(3)#

#(color(red)(cancel(color(black)(3)))d)/cancel(color(red)(3)) = 4#

#d = 4#