Question

How do you solve `(2x+3)(x+4)=1` for x using the square root property?

Answer 1

`(2x+3)(x+4)=1`
`2x^2+7x+12 =1`
`2(x^2+7/2x+49/16)+12-49/8=1`
`2(x+7/4)^2+47/8=1`
`2(x+7/4)^2=-39/8`
`(x+7/4) = \pm sqrt(39/16)i`
`x = (-7+- sqrt(39)i)/4`