Question #30ce2

1 Answer
Sunayan S
Jul 3, 2017

The retardation is #2ms^-2# and distance traveled is #125m#.

Explanation:

The retardation is #(30-20)/5##ms^-2#=#2ms^-2#.
We know the formula #v^2=u^2+2as# where #v,u,a & s# are respectively final velocity,initial velocity, acceleration/retardation and displacement.
#S=(v^2-u^2)/2a=(30^2-20^2)/(2×2)=125m#

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