Question #121d0

3 Answers
Jul 3, 2017

#9#

Explanation:

The discriminant #Delta# of some quadratic expression #a x^(2) + b x + c# is in given by #b^(2) - 4 a c#.

Let's apply this to our quadratic expression #2 x^(2) - 7 x + 5#:

#Rightarrow Delta = (- 7)^(2) - 4 (2) (5)#

#Rightarrow Delta = 49 - 4 (10)#

#Rightarrow Delta = 49 - 40#

#therefore Delta = 9#

Therefore, the discriminant of the given quadratic expression is #9#.

Jul 3, 2017

See a solution process below:

Explanation:

The quadratic formula states:

For #ax^2 + bx + c = 0#, the values of #x# which are the solutions to the equation are given by:

#x = (-b +- sqrt(b^2 - 4ac))/(2a)#

The discriminate is the portion of the quadratic equation within the radical: #b^2 - 4ac#

If the discriminate is:
- Positive, you will get two real solutions
- Zero you get just ONE solution
- Negative you get complex solutions

To find the discriminant for this problem substitute:

#2# for #a#

#-7# for #b#

#5# for #c#

#-7^2 - (4 * 2 * 5) => 49 - 40 => 9#

Jul 3, 2017

The discriminant is 9.

Explanation:

The discriminant, d, for a quadratic expression of the form #ax^2+bx+c# is:

#d = b^2-4(a)(c)#

For the given expression, #2x^2-7x+5#, the discriminant is:

#d = (-7)^2-4(2)(5)#

#d = 49-40#

#d = 9#