How do you solve the following system: $8x-7y=-39, 7x-2y= -67$ ?

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Answer 1 · 2017-07-05T12:00:14

By arranging equations. $x=-391/33$ and $y=-263/33$

Multiply the first equation by $-2$ and the second by $7$ :

$-16x + 14 y = 78$
$49x - 14 y = -469$

Add these equations (provided above), yielding

$49x-16x = -391$

$33x = -391$

$x = -391/33$

When you put this value for $x$ (for instance in the first original equation), you will find $y$ .

$8 xx(-391/33) - 7y = -39$

$-7y = -39 + (3128)/33$

$-7y = (-1287 + 3128)/33$

$-7y = 1841/33$

$y = -1841/231$

$y= -263/33$

How do you solve the following system: 8x-7y=-39, 7x-2y= -67 8x-7y=-39, 7x-2y= -67 ?