How do you find the points that the line tangent to #f(x)=x/(x+2)# has a slope 1/2?
1 Answer
Jul 9, 2017
The two points are (0,0) and (-4,2).
Explanation:
Known fact- f'(x)/gradient = 1/2.
Thought process- what are some possible values of (x,y) when f'(x) = 1/2?
f(x) = 1 - 2/(x+2) (By long division)
f'(x) = 0 - (-1)
= 2/
f'(x) = 1/2
1/2 = 2/
When x = 0
f(0) = 0
when x = -4
f(-4) = 2
The two points are (0,0) and (-4,2).