A balanced lever has two weights on it, one with mass $6 kg$ and one with mass $5 kg$ . If the first weight is $3 m$ from the fulcrum, how far is the second weight from the fulcrum?

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Answer 1 · 2017-07-09T07:54:59

The distance is $=3.6m$

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The mass $M_1=6kg$

The mass $M_2=5kg$

The distance $a=3m$

Taking moments about the fulcrum

$M_1*a=M_2*b$

$b=M_1/M_2*a=(6g)/(5g)*3=18/5=3.6m$

A balanced lever has two weights on it, one with mass 6 kg6 kg and one with mass 5 kg5 kg. If the first weight is 3 m 3 m from the fulcrum, how far is the second weight from the fulcrum?