What is the standard form of #y= (x+5)(x-2)^2 #?

1 Answer
Jul 12, 2017

See a solution process below:

Explanation:

First, expand the term being squared on the right hand of the equation using this rule:

#(a - b)^2 = a^2 - 2ab + b^2#

Substituting #x# for #a# and #2# for #b# gives:

#y = (x + 5)(x - 2)^2#

#y = (x + 5)(x^2 - (2 * x * 2) + 2^2)#

#y = (x + 5)(x^2 - 4x + 4)#

Next, we can multiply the two remaining terms by multiplying each term in the parenthesis on the left by each term in the parenthesis on the left:

#y = (color(red)(x) + color(red)(5))(color(blue)(x^2) - color(blue)(4x) + color(blue)(4))#

Becomes:

#(color(red)(x) xx color(blue)(x^2)) - (color(red)(x) xx color(blue)(4x)) + (color(red)(x) xx color(blue)(4)) + (color(red)(5) xx color(blue)(x^2)) - (color(red)(5) xx color(blue)(4x)) + (color(red)(5) xx color(blue)(4))#

#y = x^3 - 4x^2 + 4x + 5x^2 - 20x + 20#

We can now group and combine like terms in descending order by the power of the exponent for the #x# variables::

#y = x^3 - 4x^2 + 5x^2 + 4x - 20x + 20#

#y = x^3 + 1x^2 + (-16)x + 20#

#y = x^3 + x^2 - 16x + 20#