First, expand the terms in the right parenthesis by multiply each term within the parenthesis by the term outside the parenthesis:
(x + 5) - color(red)(2)(4x - 1) = 0(x+5)−2(4x−1)=0
(x + 5) - (color(red)(2) xx 4x) + (color(red)(2) xx 1) = 0(x+5)−(2×4x)+(2×1)=0
(x + 5) - 8x + 2 = 0(x+5)−8x+2=0
x + 5 - 8x + 2 = 0x+5−8x+2=0
x - 8x + 5 + 2 = 0x−8x+5+2=0
1x - 8x + 5 + 2 = 01x−8x+5+2=0
(1 - 8)x + (5 + 2) = 0(1−8)x+(5+2)=0
-7x + 7 = 0−7x+7=0
Next, subtract color(red)(7)7 from each side of the equation to isolate the xx term while keeping the equation balanced:
-7x + 7 - color(red)(7) = 0 - color(red)(7)−7x+7−7=0−7
-7x + 0 = -7−7x+0=−7
-7x = -7−7x=−7
Now, divide each side of the equation by color(red)(-7)−7 to solve for xx while keeping the equation balanced:
(-7x)/color(red)(-7) = -7/color(red)(-7)−7x−7=−7−7
(color(red)(cancel(color(black)(-7)))x)/cancel(color(red)(-7)) = 1
x = 1