Question

A `5.95*g` mass of potassium bromide were dissolved in `400*cm^3` water ... what was the concentration of the solution in `mol*L^-1`?

Answer 1

Approx. `0.1*mol*L^-1`......................

Explanation:

We use the quotient.....`"Molarity"-="Moles of solute"/"Volume of solution"`, and we know that `1*cm^3-=1*mL-=10^-3*L`......

And thus `"Molarity"=((5.95*g)/(119.0*g*mol^-1))/(400*cm^3xx10^-3*L*cm^-3)`

`=0.125*mol*L^-1` with respect to `KBr`. What are the concentrations with respect to `K^+` and `Br^-`? Are the units I use correct?